Math word problem pls help if you can ?

Question

Train A leaves at 5 pm with speed 60 mph after 2 hours Train B leaves with speed 80 mph. At what time Train B catches up with Train A

Answer 1

Solve this with a timeline

At 5 pm: Train A leaves

6 pm: A has gone 60

7 pm: A has gone 120

8 pm: A=180  B= 80

9: A=240 B=160

10: A= 300 B= 240

11: A= 360  B=320

12: A= 420  B= 400

1 am: A= 480  B= 480 so they have traveled the same distance

1 AM is the answer

A math formula is 120+60x=80x

But you have to say that starts at 7 pm because both trains are going.

the answer to the formula is 6 so 6 hours after 7 pm is 1 AM

Answer 2

At 7PM => Train A is 120 miles away from train B

Difference in speed between Train A and Train B is 20 mph

So, Train B will be catching up Train A in 6 hrs (120/20) from 7PM i.e 1AM

Answer 3

easy way:

60mph*2hrs=120mile head start

pA (position of train A) = 120 + 60 t    ::where t is time in hrs

pB (position of train B) = 80 t              ::after 7 pm

Set them equal to see where the position is the same.

120 + 60 t = 80 t

120 = 20 t

t = 5 hrs

So they meet at 7pm + 6 hrs = 1am