Math word problems help please?

Question

A man is walking at an average speed of 4 mph alongside a railroad track. A freight train, going in the same direction at an average speed of 30 mph, recquires 5 seconds to pass the man. How long is the freight train (in feet)?

Answer 1

A man is walking at an average speed of 4 mph alongside a railroad track. A freight train, going in the same direction at an average speed of 30 mph, recquires 5 seconds to pass the man. How long is the freight train (in feet)?

vish Hi !!

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mph = 1.467 fps

Speed of the Man = 4 mph = 5.868 fps

Speed of the train = 30 mph = 44. 01 fps

in 5 sec the man travels = 29.34 ft

in 5 sec the train travels = 220.05 ft

1. - From the Diagram it is shown that Train Head and the Man inline at point S

2. - The Tail of the Train is inline with the Man at point T

So there for the Length of the Freight Train = Distance Train travel at 5 sec - Man traveled at 5 sec

Length of the Freight Train = 220.05 - 29.34

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Ans:: Length of the Freight Train = 190. 71 ft

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hope this helps

Answer 2

4 mph times 5280 = 21120 ft per hour divided by 60 = 352 ft/min and 5 sec is 1/12 min so 352 times 1/12 is 29 1/3 feet.  That's how far the man walked.

30 mph • 5280 / 60 • 1/12 is 220 ft which is how far the train goes.  Since the whole train passes the man, the end of the train is where the man is, so the train is actually 220 - 29 1/3 feet long

Answer 3

191 ft