Mathematics- algebra question?

Question

use factorisation to simplify the following expression:

(2x^2 – 4x + 2)/ 6x X (3x^2 + 3x)/(x^2 - 1)

Answer 1

Assuming the problem is:

((2x^2 - 4x + 2) / 6x) (3x^2 + 3x)/(x^2 - 1)

you've got:

((x^2 - 2x + 1) / 3x) (3x(x + 1)/(x + 1)(x - 1))

by cancelling out 2/2 from the first half, and factoring out the second half

=

(((x - 1)^2) / 3x) (3x / (x - 1))

by factoring the first half, and cancelling (x + 1)/(x + 1) from the second half

Now you can cancel 3x / 3x and (x - 1)/(x - 1), and you're left with

x-1

Answer 2

2 ( x² - 2x + 1 ) ( 3x ) ( x + 1 )

-------------------------------------

( x - 1 ) (x + 1) ( 6x )

6x (x - 1) ² (x + 1)

-------------------------

(x - 1)(x + 1) ( 6x )

x - 1