Mathematics urgent plz...logarithms?

Question

Simplyfy the following to get an expression in "a"

1. SQRT(100 a log base(10) 3)

2. sqrt(3(2 log(base3)a−log(base3)(16/9))

3. 2log(base8)asqrt(8) * ·( 8−a log(base2) 8)

Answer 1

1. SQRT(100*a*log base(10) 3)

I assume the terms are multiplied

√100 * √a * √log3

10 * √a * 0.6907396

6.907396 * √a

2. sqrt(3(2 log(base3)a−log(base3)(16/9))

let log = log base 3

√( 3*2*loga - 3*log(16/9) )

√3 * (loga² - log(16/9) )

√3 * log(9a²/16)

√3 * log(3a/4)²

√3 * 2log₃(3a/4)

3. 2log₈a√8 * ( 8−a log₂8)

can't tell where the parans are in this one.

2log₈(a√8) or 2√8log₈(a) ?? assume the first

2log₈(a√8) * ( 8−a log₂8)

multiply out

16*log₈(a√8) - (2log₈(a√8)) * (a log₂8)

here it gets complicated and I'm out of time

.