Maths question??? urgent first/best answer gets points!!!?

Question

Question:

use integral calculus techniques to determine whether your chosen car can brake faster than it can accelerate.

use one of the functions:

y= -0.135x^2 + 5.213x + 4.505

y= -2.483 + 19.7lnx

cars braking distance to go from 70mph to 0 is 173 feet

accelerates 0 to 70mph in 5.9 seconds distance 354.33 feet

Answer 1

Hey,

If you need the answers, I'll help with some physics.

Braking distance is 173 ft decelerating in t number of seconds.  To find the time, you need to use length/time^2 to find the rate of deceleration. So:

70 mph = 102.667 ft/sec

avg velocity is 102.667/2 = 51.333

d/r = t so 173/51.333 = 3.37 seconds.  And:

Acceleration = L/t^2 = 173/3.37 = -15.23 ft/sec^2

Now accelerating 0 to 70mph (102.667 ft/sec) in 5.9 sec in 354.33 ft.  The 5.9 seconds given can be compared to 3.37 seconds from the first part, so you can brake faster than accelerate.

btw. a = L/t^2 so a = 354.33/5.9^2 = 10.18 ft/sec^2.

Sorry about the integrals.