Maths table (or something like that)?

Question

A large circular table is pushed into the corner (right-angle) of a room so that it touches both walls. On the circumference is a spot which is 8 inches from one wall and nine inches from the other.

What is the radius of the table?

(Apologies for using old units but it's the only way I could make this problem feasible).

Answer 1

Recall the general equation for a circle

(x-h)² + (y-k)² = r²

The key lies in realizing that the center of the circle (h,k) lies r units from each wall.  Therefore h, k and r are all equal and the equation reduces to

(9-r)² + (8-r)² = r².

Rearrange and solve to find r = 29 (if the point on the circumerence is closer to the walls) or r = 5 (if the point lies on the "outside" of the table's circumference)

Answer 2

the diamiter is 17 inches.

the radis us 8.5

Answer 3

hhhhmmmmmmmm 17 inches sounds way too small to have that distance into the corner

I cannot figure out how to work the problem backward from your given numbers, without graphing it - and using a compass to draw the table

if it's pushed into a corner of a right angle - there shold be a spot that is equidistant from both walls

but I cannot figure that - either - so sorry for rambling

good luck