Mechanics Problem...?

Question

In the flgure below, the incline has mass M and is fastened to the stationary horizontal tabletop. The block of mass m is placed near the bottom of the incline and is released with a quick push that sets it sliding upward. It stops near the top of the incline, as shown in the flgure, and then slides down again, always without friction. Find the force that the tabletop exerts on the incline throughout this motion.

My answer is (M+m)g. But, it looks too simple to be correct. Help......

Answer 1

The normal force is equal to m*g* cos(theta)