Mendel's peas I need answer...no clue:)?

Question

In Mendel's garden peas, the yellow color is dominant to the green. Additionally, smooth seeds are dominant to wrinkled seeds. In a dihybrid cross, a plant has a P generation consisting of smooth yellow and wrinkled green. The F1 generation consists of 100% smooth yellow. These plants are now self-fertilized and the F2 generation would show a phenotype ratio of:

a. 9:3:3:1

b. 3:1:1:3

c. 2:1:1:0

d. 2:1:1:2

Answer 1

A. 9:3:3:1 ratio

This means that 9 would possess all dominant traits. Three would possess dominant color but is wrinkled. 3 would show recessive trait for color but is smooth. One would manifest both recessive traits.

Hope this helps...

Answer 2

it would be B. 3:1; 1:3

Answer 3

The phenotypic ration in this case is 9:3:3:1 .

Meaning out of every 16 plants such obtained 9 will be yellow and smooth, 3 yellow and wrinkled, 3 green and smooth and 1 will be green and wrinkled

You can check it from the punnett square