Molarity question?

Question

How would you make a .069M solution of HCL from a 12 M solution of HCL?

Answer 1

the equation is M1V1=M2V2...now you either need to know V1 or V2.

Answer 2

You dilute it.  Use the handy-dandy relation

(Volume x 12 M)stock = (Volume x 0.069 M)desired solution.  Basically, each ml of stock solution will yield 12/0.069 mL of desired solution.

Answer 3

These dilution type problems are best solved by

C1V1 = C2V2.  Let's make 1 L of 0.069 M HCl.

C1 = concentration of original solution = 12 M

C2 = conventrationm of diluted solution = 0.069 M

V1 = volume of original solution = ?

V2 = volume of diluted solution = 1L

(12 M)(V1) = (0.069 M)(1 L)

V1 = 0.069 / 12 = 0.0058 L = 5.8 mL

Take 5.8 mL of 12 M HCl, dilute to a final volume of 1 L, and mix.