Question:

More Systems of equations?

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Solve.

1.) X+Y+Z=20000

2.) .05X+.07Y+.10Z=1390

3.) X=Z+3000

PLEASE SHOW ALL WORK!!

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1 ANSWERS


  1. X + Y + Z = 20000

    .05X + .07Y + .10Z = 1390

    X = Z + 3000

    Solve the first equation for Y.

    X + Y + Z = 20000

    Y = 20000 - Z - X  

    Call this equation *1*

    Substitute *1* and the third equation into the second equation and solve for Z.

    .05X + .07Y + .10Z = 1390

    .05(Z + 3000) + .07(20000 - Z - X) + .1Z = 1390

    .05(Z + 3000) + .07(20000 - Z - (Z + 3000)) + .1Z = 1390

    .05Z + 150 + .07(20000 - Z - (Z + 3000)) + .1Z = 1390

    .05Z + 150 + 1400 - .07Z - .07(Z + 3000) + .1Z = 1390

    .05Z + 150 + 1400 - .07Z - .07Z - 210 + .1Z = 1390

    .05Z + 150 + 1400 - .14Z - 210 + .1Z = 1390

    .05Z + 1400 - .14Z - 60 + .1Z = 1390

    .05Z + 1400 - .04Z - 60 = 1390

    .05Z + 1340 - .04Z = 1390

    .01Z + 1340  = 1390

    .01Z = 50

    Z = 5000

    Substitute this into the third equation and solve for X.

    X = Z + 3000

    X = 5000 + 3000

    X = 8000

    Substitute this into *1* and solve for Y.

    Y = 20000 - Z - X  

    Y = 20000 - 5000 - 8000

    Y = 7000

    Answer:  X = 8000, Y = 7000, Z = 5000

    Hope this helps you!

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