More practice problems?

Question

I need help on the following problems, and all steps and formulas would greatly needed:

express answer in either slope-intercept and standard form.

1. Through the points (3,-2) and (-6,10)

2. Parallel to y= -3x + 10 and through the point (-5,7)

3. Graph x-3y >12

Answer 1

Slope-intercept form is y = mx+b

Standard form is Ax + By = C, where A, B, and C are integers and A > 0.

1.  Find the slope.

m = (-2-10)/(3-(-6)) = -12/9 = -4/3

Then y = (-4/3)x + b

Use either point to find b.

-2 = (-4/3)(3) + b

-2 = -4+b

2 = b

The slope-intercept form is y = (-4/3)x + 2

I'll let you convert it to standard form (Hint: You will add (4/3)x to both sides, then multiply both sides by 3).

2.  Parallel lines have the same slope.

That means your line will look like y = -3x+b

Use the given point to find b (like I did above).

3.  x - 3y > 12

First graph the line x-3y = 12.  It will be dashed.

Then to determine which side to shade, pick any point not on the line, and plug it into the inequality x-3y > 12.  If the result is true, shade the side where the point is.  If the result is false, shade the opposite side.