Multiply these Brackets and Simplify.?

Question

(x+2)(x+3)

Moving into Year 8 and Level 7 work. Don't make it complicated because I wont understand!

Answer 1

x^2+2x3x+6

x^2+5x+6

Answer 2

You need to foil the problem.  "FOIL" stands for first, outside, inside, last.

So you have (x+2)(x+3).

First, Outside:

Multiply the first x by the second x. = x^2.

Then Multiply the first x by the 3. = 3x.

Inside, Last:

Multiply the 2, by the second x. = 2x.

Then Multiply the 2 by the 3. = 6.

Now add all of your answers up exactly how you got them.

x^2 + 3x + 2x + 6

x^2 + 5x + 6

For any of these problems, the easiest method is always as follows.

(a + b)(c + d)

* keep in mind the c would usually be an a, but I just want to show you how this works without having to say 'first a' and 'second a'.

ac + ad + bc + bd.

Answer 3

you use a method called FOIL-ing

F - First

O - Outer

I - Inner

L - Last

so what i mean is if you have this problem

(x + 2)(x + 3)

you first multiply the first terms which is x and x

so x * x = x^2 (x squared)

then you multiply the outter terms which is the first x and the three so x * 3 = 3x

then you multiply together the inner terms which is 2 and the 2nd x so 2 * x = 2x

then the last terms which also means the last terms in each group so 2 * 3 = 6

so what you have right now is x^2 + 2x + 3x+ 6

finally you have to simplify so add 2x and 3x together

so your final answer is x^2 + 5x + 6

Answer 4

x² + 5x + 6 is the answer

Here's why:

x (x + 3) = x² + 3x

2 (x + 3) = 2x  + 6

Answer 5

We call these problems FOIL. This stands for

First

Outter

Inner

Last

This in the order in which you multiply.

First x*x

Outter x*3

Inner 2*x

Last 2*3

This gives you (That's the Multiply)

x^2 + 3x + 2x +6

Combine your like terms of 3x + 2x (That's the Simplify)

x^2 + 5x + 6

Answer 6

Use FOIL method - Front, Outside, Inside and Last...

x times x

x and 3

2 and x

2 and 3

...............

(x*x)+(x*3)+(2*x)+(2*3)

x^2+3x+2x+6

---------->::: x^2 + 5x + 6

10 Points please....