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NEED HELP FINDING THE PERIOD OF Y= -2 COS (3X+pi/2)?

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NEED HELP FINDING THE PERIOD OF Y= -2 COS (3X+pi/2)?

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  1. Period is simply 2π divided by the coefficient of x which is

    2π/3


  2. the effect of the 2 is to make the graph taller.

    the minus infront turns it upside down

    the pi/2 merely shifts it horizontally (to the right)

    so all you need to look at is the 3 which makes three full cycles of the cos graph in 360degrees or 2pi.

    (3 times per 2pi)

    the frequency upside down is the period. (important concept T=1/f)

    so the period is 2pi/3

    Some people use the rule T=2pi/n

  3. The period of y = cos (bx) is:

    (2π) / | b |

    y = -2cos (3x + π/2)

    Period = (2π) / | 3 |

    Period = (2/3)π

    π/2 is simply a phase shift.

    Phase shift = -c / b

    Phase shift = -(π/2) / 3 = - (π / 6)

  4. y = - 2 cos (3x + π/2)

    Period = 2π / 3
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