Need Help! PLEASE ANSWER AS SOON AS POSSIBLE?

Question

A block of mass 2kg rests on a plane inclined at 30 degrees with the horizontal. The coefficient of friction between the block and the surface is 0.7. Calculate the frictional force acting on the block?

The answer is 9.8 N. BUT I DON'T KNOW HOW ?

Answer 1

Since the block is at rest, it follows that the friction force is equal to component of the weight of the block along the incline downward.

Let Wx = weight of the block along the incline downward.

     Wx = Weight of Block x sin 30 deg

     Wx = (mg)(sin 30 deg)

     Wx = (2kg x 9.8 m/s^2)(sin 30 deg)

     Wx = 9.8 N     ANSWER

Hope this helps.

teddy boy