Need assistance to solve 2x^2 = 9x –4 and 6x^2 –x –2 =0?

Question

Thanks in advance

Answer 1

Are these 2 separate equations or a system of equations?  Once you let me know, I can solve them accordingly. :)  Please let me know!

Answer 2

2x^2 = 9x –4

2x^2 -9x +4=0

x=4

x=1/2

6x^2 –x –2 =0

x= -1/2

x=2/3

Answer 3

write them so all the x variables are on one side

0 = -2x^2 + 9x - 4  and 0 = 6x^2 - x - 2

if you can, factor out any common factors (in this case, you can not for either equation)

You could use the quadratic formula or just a little trial and error to factor the equations.

The first one is easy to factor using trial and error

What factors of -2 and -4 would multiply then add up to 9?  Factors for -2 are -2, 1, -1, 2 and factors for -4 are -4, 1, -2, 2, -1, 4

Plug any of those combinations in the formula x 0 = (?x+?)(?x+?)

In this case, 0 = (-2x+1)(x-4), then make each paretheses equal to 0 and solve for x (solution:  x = 1/2 or 4)

Both equations would probably be more easily solved using the quadratic formula (link below)

Answer 4

a) 2x^2=9x-4

2x^2-9x+4=0

factor:

(2x-1)(x-4)=0

x=1/2, x=4

b)  6x^2-x-2=0

factor:

(3x-2)(2x+1)=0

x=2/3, x=-1/2