Need chemistry help!!! please! please!?

Question

1. consider the balanced equation Al2O3+ 3Cu→ 2Al + 3CuO. if you have one mole of Al2O3 and an unlimited amount of Cu, how many moles of Al can you produce?

2. if you have 408 grams of Al2O3 and an unlimited supply of Cu, how many grams of Al can you produce (rounded to the nearest gram)? show calculations.

please please help me!!

Answer 1

per the reaction formula: 2



408 g Al / 82 g/mole = 4.97 moles x 2 x 27 g/mole = 268.38 g Al  

Answer 2

Two mole of Al in 1 mole of Al2O3

g Al = [(2*AtWt Al)/(formulaWt of Al2O3)]*408

Plug and solve.