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Question

is y=x^2+1 a function? State its domain and range.pls explain ur answer

thanks in advance

Answer 1

The domain is all of the x&#039;s on the graph. There is no limit to the x&#039;s on this parabola.

The range is all of the y&#039;s on the graph. The y value cannot go below 1 because x^2 must be positive

The domain is (-infinity,infinity) or all reals

The range is [1,infinity)

It is a function, because it passes the vertical line test when graphed.

Answer 2

yes it is because of the  ^2. thats all i can really explain without paper

Answer 3

kids these days are getting good. i wish yahoo answers was around when i went. wait! college, here i come!

Answer 4

No its not...Its y = x^2 function

can&#039;t really explain its kinda hard.

Answer 5

The domain is the interval of x values such that y is real. It is easy to see that x can be any real number and it will always produce a real y value. Therefore, the domain is x: (-infinity, +infinity); i.e. all real x values. Notice how I used ( ) rather than [ ], which indicates that the interval does not have any boundaries. How can infinity have a boundary?

The range is the interval of y values that can exist. For example, if you inspect the function, y can never be less than 1 because the x^2 function is always positive even when x &lt; 0. When x = 0, y = 1. When x = -1, y = 2. When x = 1, y = 2. When x = -2, x = 5. When x = 2, y = 5. You see? Thus, the range is y: [1 , infinity). The [ next to the 1 indicates that 1 is included in the range, but values less than 1 are not included.  

Answer 6

yes, for each value of x there&#039;s only 1 value of y, so it&#039;s a function

domain is all real numbers

range is y ≥ 1

if x = 0, y = 0² + 1 = 1, and if x is not 0, x² will be positive, making y &gt; 1.