Need help finding the density of sand particles in an experiment.

Question

Here's the experiment:

An experiment was performed in which an empty 100 mL graduated cylinder was weighed. It was weighed once again after it had been filled to the 10.0 mL mark with dry sand. A 10 mL pipet was used to transfer 10.00 mL of methanol to the cylinder. The sand-methanol mixture was stirred until bubbles no longer emerged from the mixture and the sand looked uniformly wet. The cylinder was then weighed again. Use the data obtained from this experiment (and displayed at the end of this problem) to find the density of each of the following.

Displayed information:

Mass of cylinder plus wet sand 45.2613 g

Mass of cylinder plus dry sand 37.3488 g

Mass of empty cylinder 22.8317 g

Volume of dry sand 10.0 mL

Volume of sand methanol 17.6 mL

Volume of methanol 10.00 mL

I correctly found the density of:

dry sand 1.45 g/mL

methanol 0.7913 g/mL

I need help finding the density of sand particles. This differs from dry sand in that sand particles wants you to eliminate the air that may be between the sand particles. Thanks!!

Answer 1

you found that you had 14.5171 grams of sand

& you found that when you added 10.00 ml of methanol, the level rose to 17.6 ml, after ensuring that methanol had filled all the air spaces.

this means that the sand particles occupied 7.6 ml of the 17.6 total

density of sand particles:

14.5171 grams sand / 7.6 ml= 1.91 g/ml

your answer ( @ 2 sig figs) : 1.9 g/ml