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Need help how to solve for λ: Z2( 1 – λ/2a) = k ?

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Need help how to solve for λ: Z2( 1 – λ/2a) = k ?

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  1. Z2( 1 – λ/2a) = k

    2aZ2 -Z2λ = 2ak

    λ = (2ak - 2aZ2)/z2 = 2a(k/z2 -1)

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