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Need help please with this calculus question?

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Evaluate:

LIMIT x ==> INFINITY of lnx/x^2

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3 ANSWERS


  1. As x goes to infinity, x² gets larger and larger than the numerator.

    lim x→∞ ( ln(x) / x² ) = 0


  2. Use L'Hospital's rule:

    lim x-> inf lnx/x^2 = lim x_>inf (1/x)/2x = lim x->inf 1/2x^2 = 0


  3. limit is 0 even (lnx )/(x) is 0so x^2 it is 0

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