Need help with PROBABILITY...?

Question

the probability that a man watches a certain television show is 0.4 and 0.5 for a married woman.

The probability than a man watches the show given that his wife does is 0.7, find the probability that:

a) a married couple watches the show

b) a wife watches the show given that the husband does

Answer 1

M - Man watches the show

W - Wife watches the show

P(M)=0.4

P(W)=0.5

P(M/W)=0.7

a) P(M and W) = P(W) P(M/W)

= (0.5)(0.7)=0.35

b) P(W and M) = P(M) P(W/M)

0.35 = 0.4 P(W/M)

P(W/M) = 0.35/0.40

=35/40 = 7/8

Answer 2

qa

P(man watch | wife watch)

= P(couple watch) / P(wife watch)

= P(couple watch) / 0.5

= 0.7

P(couple watch) = 0.5 * 0.7 = 0.35

qb

P(wife watch | husband watch)

= P(couple watch) / P(man watch) <-- assuming all men watching are married

= 0.35 / 0.4

= 0.875  

Answer 3

P(Man)=0.4

P(Woman)=0.5

P(Man/Woman)=0.7

a) P(Man and woman)=P(woman)*P(Man/woman)

                                =0.5*0.7=0.35

b) P(woman/man)=P(man and woman)/P(man)

                          =0.35/0.4=0.875

I hope this can be useful

David

Answer 4

I did not complete the class in probability. I had to drop out and take another class in place of it. It just never made sense to me. I was a senior EE major, and failing probability. Good luck, give me y=mx+b

I can solve that one.

a: guessing 0.4 x 0.5 = .2

b: more guessing, same as above .2