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Question

I'm doing my summer math packet for algebra and i reached a problem that stumped me. I haven't done a problem like it for a while. Can someone help me. The problem is 7(3-6)=6(4+t) I need to find the value of t

Answer 1

t= -7.5

x= -20

Answer 2

First multipy the number outside of the parantheses

21- 42 = 24 + 6t then subtract 42

-21 = 24 + 6t then subtract 24 from both sides

-21 - 24 = 6t

- 45 = 6t then divide each side by 6

t = -45/6

God, what an ugly fraction

Answer 3

first one is easy do 3-6 first to get -3      7x-3=-21   so 6(4+t)=-21 so 6x?=-21 so do opposite to figure out answer -21/6 -3.5 so 4+?=3.5

-.5 so t=-.5 happy to help now for the second question ...

you want to find the one without variable first so 5(7-(-2) not hard at all 7- -2=9 5x9=45 so 3(5+x) has to = 3 times what = 45. . .15 so 5+? = 15? 10 so x=10

short and simple the answers are t=  -.5 or -1/2   and x= 10

happy to help

Answer 4

7(3-6)=6(4+t)

Well 1st of all you multiply out the two sides.

So you get:

21-42=24+6t

then you do whatever sums you can do:

-21=24+6t

then you have to get t on its own so you bring the 24 across and change the sign:

-21-24=6t

therefore 6t=-45

therefore t=-45/6

Follow the same method to work out the 2nd equation.

Answer 5

1) 7(3-6)=6(4+t)

7(-3)= 24+6t

  -21-24= 6t

   -45=6t

   -7.5=t

2) 15+3x= 5(9)

    3x=45-15

    3x= 30

    x=10