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Need help with a physics problem: Non-constant acceleration. (Includes differential equations)?

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I'm working on a physics problem, and can't manage to solve it. Should I be working towards a second order differential equation? How would I solve that if I get to it?

"For a spherical celestial object of radius R, the acceleration due to gravity g at a distance x from the center of the object is g=(go)(R^2)/(X^2), where go is the acceleration due to gravity at the object's surface and x>R. For the make, take go=1.63 m/s^2 and R=3200km. If a rock is released from rest at a height of 4R above the lunar surface, with what speed does the rock impact the moon?"

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  1. The acceleration is the second derivative of the position with respect to time, right?, So:

    a = d^2xdt^2 = -(g0*R^2)/x2  

    (The negative sign is because the direction of acceleration is downward, toward the center of the moon)

    This is a nonlinear second order differential equation.  Notice that the independent variable, t, does not appear explicitly.  In such cases, it turns out that making the substitution, v = dx/dt will usually simplify the equation.

    Define v = dx/dt

    then d^2xdt^2 = dv/dt = dv/dx * dx/dt = dv/dx * v

    Substituting v*dv/dx for d^2xdt^2 in the original equation we get:

    v*dv/dx = -(g0*R^2)/x2

    This is now a separable first order equation, and even better, it gives the speed of the rock (v = dx/dt) as a function of position, which is exactly what we need to find.

    Separating variables, we get:

    v dv = -(g0*R^2) * dx/(x^2)

    (1/2)*(v^2 - v0^2) = -(g0*R^2)*(1/x0 - 1/x)

    v^2 = v0^2 - 2*(g0*R^2)*(1/x0 - 1/x)

    We know that initially, v0 (the initial speed) is zero, and that the rock is dropped from a distance 5R from the center of the moon's center (4R above the surface of the moon), and we are interested in the value of v when x = R:

    v^2  = -2*(g0*R^2)*(1/(5R) - 1/R)

    v^2 = 2*(g0*R^2)*(4/5R)

    v^2 = 8*g0*R/5

    Plugging in the values for g0 and R, we get:

    v^2 = 8*(1.63 m/s^2)*(3.2*10^6 m)/5

    v^2 = 8.346*10^6 (m/s)^2

    v = 2889 m/s

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