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Need help with maths question?

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y = x^2 (3x+4)^3

dy/dx = 16x(3x+4)^2 - This answer is incorrect - explain the error and explain the correct answer.

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  1. y = [x^2 ]*[(3x+4)^3]

    dy/dx = [(3x+4)^3](2x) + [x^2](2(3x+4)^2)(3)


  2. dy/dx=2x(3x+4)^3+x^2*(3)*(3x+4)^2

             =[6x^2+8x+3x^2](3x+4)^2

             =[9x^2+8x](3x+4)^2
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