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Question

You burn natural gas as shown in the reaction below. What weight of water will be given off when 0.32 g of natural gas (CH4) is burned with excess oxygen?

CH4 + 2O2 ----> CO2 + 2H2O

Answer 1

molar mass of CH4 is 12,01 + 1,008 x 4 0 = 16,042 g/mol

the number of moles contained in 0,32 of CH4 will be: n of moles = mass / molar mass --> 0,32 / 16,042 = 0,0199 mol

The reaction says that 1 mol of CH4 gives 2 moles of H2O

The molar mass of H2O is 16 + 1,008 x 2 = 18,016 g / mol and so its mass will be: mass = molar mass x number of moles --> 18,016 x 0,0398 = 0,717 g

Answer 2

Moles CH4 = mass / molar mass = 0.32 g / 16.043 g/mol =0.0200

the ratio between CH4 and H2O is 1 : 2

Moles water = 2 x 0.0200 = 0.0400

Mass water = moles x molar mass = 0.0400 x 18 g/mol =0.72 g