Question:

Need help with this fraction question?

by Guest65984  |  earlier

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Appreciate any help solving this problem

The equation is 1/a= 1/b + 1/c. Solve the equation in terms of a. Your final answer should have the variable a isolated on one side and the rest of the variables on the other side.

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  1. 1/a = 1/b + 1/c

    **divide all sides by 1**

    idk how to explain this...

    all i know is that a=b + c because a,b,and c all have the same # (1) in front


  2. LCD is abc so multiply it out to get

    bc = ac + ab

    bc = a(c + b)

    bc/(c+b) = a

    Have a good day!

  3. i know u dont want want to here this but DO IT YOURSELF

  4. take the reciprocal of both sides... a = 1/(1/b + 1/c)

    combine the fractions .... a = 1/(c/bc + b/bc) = 1/( (c+b)/bc )

    simplify.... a = bc/(c+b)

  5. 1/a = 1/b + 1/c

    thus, using common denominators, 1/a = (1xc + 1xb)/(bc)

    thus, the {inverse of 1/a} = a = (bc)/(c + b)

    the answer is (bc)/(c + b)

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