Need some help over integrals?

Question

How can I solve this:

∫(x + 3)100dx

thanks..

Answer 1

take out the common factor of 100 so you get

100∫(x + 3)

then you just integrate that which comes out to be x^2/2 + 3x

and multiply it by 100 giving you

50x^2 + 300x + c

Answer 2

∫(x + 3)100dx

=> ∫(100x + 300)dx

=> ∫100x.dx + ∫300.dx

=> 100 * (x^2)/2 + 300x + C

=> 50x^2 + 300x + C

Answer 3

∫(x + 3)^100dx

= (1/101)(x + 3)^101  + c

Answer 4

[(100x + 300)dx]

= (100x^2)/2 + (300x)

=50x^2 + 300x

pretty sure thats right

Answer 5

Tonya is correct... never forget to add a +c at the end

for open ended intergrals