Question:

Need to calculate volume in cubic yards?

by Guest34223  |  earlier

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I need to fill two containers, one 17x18ft, the other 16x17ft, each to a depth of 4-5in. The material I need to fill with comes in cubic yards, how much will I need?

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  1. V = lwh or Ah; where: A = lw.     Given h = 4 "

         h = 4 "/12 "/' = 0.33... '

       For a container of 17 ' x 18 ':  

    V = Ah; A = 17 ' x 18 ' = 306 '2

    V = 306 '2 x 0.33... '

    V = 102 '3;     1 yd. = 3 ';     1 yd.3 = (3 ')3 = 27 '3

    V = 102 '3/27 '3/yd.3

    V = 3.77... yd.3 or 3 7/9 yd.3

              if h = 5 "

         h = 5 "/12 "/' = 0.4166... '

    V = 306 '2 x 0.4166... '

    V = 127.5 '3/27 '3/yd.3

    V = 4.72... yd.3 or 4 13/18 yd.3

       For a container of 16 ' x 17 ':

    V = Ah; A = 16 ' x 17 ' = 272 '2

    V = 272 '2 x 1/3 '

    V = 90.66... '3;     1 yd. = 3 ';     1 yd.3 = (3 ')3 = 27 '3

    V = 90.66... '3/27 '3/yd.3

    V = 3.36 yd.3 or 3 29/81 yd.3

              if h = 5 "

         h = 5 "/12 "/' = 0.4166... '

    V = 272 '2 x 0.4166... '

    V = 113.33... '3/27 '3/yd.3

    V = 4.20 yd.3 or 4 16/81 yd.3

    If we select a depth of 5 inches as the maximum height, then from the solution above:

    V1 = 4 13/18 yd.3

    V2 = 4 16/81 yd.3

    Therefore the volume of each container including space allowance must be 5 cubic yards.


  2. Four inches is 1/3 foot. So 17x18/3, or 102 cuft, plus 17x16/3, or 96 cuft, hence 198 cuft, divided bt 27. Same basic result for the concrete truck.

  3. Multiply the length by the width by the depth,  with all expressed in feet. Divide that number by 27 which is the number of cubic feet in each cubic yard. Do both containers and add to get the total.

  4. just remember there are 3 feet per yard so calculate the volume of each space length x width x height and divide by 27.  3x3x3=27  This will get you from feet to yards.

  5. If you fill the containers to a depth of 5 inches, the first container holds a volume of:

    V = 17*18*(5/12) ft^3

    V = 127.5 ft^3

    and the second container holds a volume of

    V = 16*17*(5/12) ft^3

    V = 113.3 ft^3

    Adding these together, we get 240.83 cubic feet.  Since a yard is 3 feet long, there are 3*3*3 = 27 cubic feet in a cubic yard.

    240.83 ft^3 = 8.920 yd^3

    You'll need 9 cubic yards.

  6. 17 ft. x 18ft. =306 sq. ft.

    16 ft. x 17 ft. = 272 sq. ft.

    306 + 272 =578 sq. ft.

    5 in.  = .417 ft.

    578 x .417 = 241 cu. ft.

    241 cu. ft. / 27 = 8.9 cu. yd.

    If you get 9 yds. you should have a little left.

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