Question:

Negative to the e (horizontal asymptotes)?

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lim 5/3+2e^-x and lim 5/3+2e^-x

x->infinite x->-infinite

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  1. limit of e^-x is 0 so,

    2 * 0 = 0 and,

    5/3 + 0 = 5/3

    You must have a typo in your 2nd problem (repeated?), but the principle is the same.

    .

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