Question:

Net force of crewmen pulling boat?

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Two crewmen pull a boat through a lock. One crewman pulls with a force of size F1 = 135 N at an angle of = 31° relative to the forward direction of the boat. The second crewman, on the opposite side of the lock, pulls at an angle of 45°. How large a force F2 should the second crewman pull so that the net force of the two crewmen is in the forward direction?

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  1. Hi, Dorthy--

    Draw a pic.  It really helps!

    For the force to be all forward, the lateral forces must be equal..

    so,

    135 sin (31) = F sin (45)..you should get 98.3 N

    The forward F will be what??

    135 cos 31 + 98.3 * cos (45)

    -Fred

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