Neutralization Reaction Question?!?

Question

A dilute solution of acetic acid is called vinegar. Acetic aced reacts with sodium hydroxide according to the equation

A 5.00 mL sample of vinegar needed 42.5 mL of 0.115M NaOH to reach the equivalence point

a. Calculate the molarity of the vinegar

b. Calculate the percent (m/v) of vinegar in the sample

c. What type of Chemical Reaction does this represent?

Answer 1

since Acetic acid & NaOH react on a 1mole to 1 mole basis, I can use the simplified equation:

M1V1 = M2V2

(0.115M)(42.5ml) = (M) (5.00ml)

your answer: 0.978 Molar vinegar

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b. Calculate the percent (m/v) of vinegar in the sample

find the mass of acetic acid in one litre of solution, using molar mass:

0.978 moles  @ 60.05 g/mol = 58.7 grams

find the %(m/v):

58.7 grams of acid / 1000ml solution times 100 = 5.87 %

your answer is 5.87%

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c. What type of Chemical Reaction does this represent?

this neutralization reaction is a style of double replacement   reaction, also known as a  Double displacement reaction, or a Metathesis