Never done this type of equation before???

Question

how do you solve this:

2x^2-5x+2=1

Answer 1

first step make it equal to zero

2x^2-5x+2=1

2x^2-5x+2-1=0

2x^2-5x+1=0

now u will need to use the quadratic formula when a=2 b=-5 c = +1

x = -1*b+-√(b^2-4*a*c)/ 2a

Answer 2

2x^2-5x+1=0        a=2   b= -5  c= 1

x1.2 =  -b(+/-)√b^2-4ac

            ---------------------

                     2a

  

     5(+/-)√25-4*2*1  

=  ----------------------

                  2*2

   5(+/-)√25-8

=----------------

          4

    5+√17

=----------   OR

       4

5- √17

---------

    4

Answer 3

This is a quadratic.  It's called that any time the highest power is 2.  To solve it, first put it into standard form by subtracting 1 from both sides:

2x^2 - 5x + 2 = 1

2x^2 - 5x + 1 = 0

At this point, you have three options:  you can factor it, you can complete the square, or you can use the Quadratic Formula.  Usually, one starts with factoring, but it turns out this one doesn't factor.  If you've never seen one before, I have no idea how your teacher expects you to do it.  So - at this point, I'd wait until Monday and ask.  If you really want to solve it, Google the Quadratic Formula.