Not asking for much; but 1 simple question Help? i dont udnerstand? help me?

Question

5) A lot for a new house has the shape of a polygon with three right angle corners as shown below. A 125-degree angle is formed at the fourth corner and the value of the angle at the fifth corner is unknown. (a) What is the measure of the exterior angle adjacent to the 125-degree angle? (b) What is the sum of the five angles in a pentagon? [Hint: Sum = 180(n – 2)] (c) What is the measure of the angle formed at the fifth corner (x)?

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Answer 1

The exterior angle is the supplement of the interior angle (125-degrees), therefore it is 180 - 125 = 55 degrees.

The sum of the angles of any pentagon is given by the hint:

180 (n-2)= 180 (5 - 2) = 540 degrees

Add the four given angles and subtract from 540 to get the fifth angle:

270 + 125 = 395

540 - 395 = 145 degrees

Answer 2

exterior angle= 180 - 125= 55

sum of the angle of any polygon is 180(n-2)  n is the number of sides

so for a pentagon it is

     180X3=540

angle formed at the fifth corner (x)= 540-(90+90+90+125)

Answer 3

The exterior angle can be found by subtracting 125 from the angle of a straight line (180 degrees).  The sum of the five angles has already been given to you in the hint (n = the number of sides of the polygon, or 5).  x is the same as the exterior angle plus 90.