Okay, This is a an area of rectangle type problem...?

Question

Here it is.. Please help!!!

http://www.mathhelpforum.com/math-help/179466-post6.html

Answer 1

The solution on the page linked is wrong.

They used the formula for the perimeter instead of the area.

Area = W × L

Let x = twice the width of the frame (both sides)

(23 - x) (21 - x) = 292

483 - 44x + x² = 292

x² - 44x + 191 = 0

2x = 44 ± sqrt(44² - 4×191)

2x = 44 ± sqrt(1172)

2x = 44 ± 34.234

x = 22 ± 17.117

+ root is too big

- root is 4.883 = x

Width of frame is 2.4415 = x/2

21 - 4.883 = 16.117

23 - 4.883 = 18.117

16.117 × 18.117 = 291.99

Done.