Operations on Complex Numbers. Mutliple choice given.Please help.?

Question

Perform the indicated operations, then simplify.

1. (-3+i) + (4+6i) =

A. 7 + 7i

B. 1 + 6i

C. 1 + 7i

D. -1 + 7i

2. (-4 - 6i) + (-2 - 3i)

A. -2 - 9i

B. -6 - 3i

C. -2 - 3i

D. -6 - 9i

3. (-4 - 6i) + (-2 - 3i)

A -2 - 9i

B -6 - 3i

C -2 - 3i

D -6 - 9i

4. (-2 + 5i) + (-4 - 2i)

a. 2 + 7i

b. -6 + 7i

c. 2 + 3i

d. -6 + 3i

5. (4 + 2i)(3 - i)

a. 14 + 2i

b. 10 + 2i

c. 14 - 2i

d. 10 - 2i

6.(-3 + i)(2 + 7i)

a. -13 + 19i

b. 1 + 19i

c. -13 - 19i

d. 1 - 19i

7. (5 + 2i)(5 - 2i)

a. 29 - 20i

b. -29 + 20i

c. 21

d. 29

8. 4+2i/3-i

A.7+5i/5

B.5+5i/4

C.7+5i/4

D.1+i

9.3+i/1-4i

A 1+12i/-15

B 1+13i/17

C 7+13i/-15

D 7+13i/17

10. -2-2i/5-2i

A-2/5

B-14-14i/29

C -6-14i/29

D -6+14i/21

Answer 1

Which ones do you need help on?  When it comes to addition/subtraction, it's the easiest form of algebra, just add/subtract.  When multiplying, i^2 = (-1).  Not too sure when you divide >_>

Answer 2

Just treat "i" like any other variable initially, add/subtract like terms, FOIL as needed, etc.

The only difference is that "i" is special in that it's defined to be √(-1)

So if you have an i², you can substitute "-1" in its place and simplify.

Answer 3

1=c

2=b

Answer 4

1. (-3+i) + (4+6i) = 1+7i

2. (-4 - 6i) + (-2 - 3i) = -6-9i

3. (-4 - 6i) + (-2 - 3i)= -6-9i

4. (-2 + 5i) + (-4 - 2i) = -6+3i

5. (4 + 2i)(3 - i) = 12-4i +6i -2i^2 = 12+2i+2 = 14+2i

You can do the rest yourself