Question:

Optimize a Hexagonal Prism of volume 500cm^3?

by Guest32399  |  earlier

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requires minimal surface area

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  1. The area is minimized with a regular hexagon cross section.

    Area = 2x(area of hexagon) + 6x(side of hexagon)x(height)

    Volume = (Area of hexagon)x(height)

    (Area of hexagon) = 3sqrt(3)s^2

    0.5 = 3hsqrt(3)s^2

    h = 0.5/{3sqrt(3)s^2}

    Area = 2x(3sqrt(3)s^2) + 6x(s)x(0.5/{3sqrt(3)s^2})

    =6sqrt(3)s^2 + 1/[sqrt(3)s]

    dA/sd = 12sqrt(3)s - 1/[sqrt(3)(s^2)] = 0

    12sqrt(3)s = 1/[sqrt(3)(s^2)]

    36s = 1/s^2

    s^3 = 1/36

    s = 1/(36)^(1/3) = 0.302853 cm

    h= 1.049115 cm

    Area = 2.859553 cm^2

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