PHP question. Program-wise, how can I extract the URL address of the website my program is currently reading?

Question

I have a URL that will bring me to another URL, and I need to extract the final URL from the final webpage.

Answer 1

<?

echo $_SERVER['HTTP_HOST'];

?>

That will spit out:

www.mydomain.com

This might help.  This will spit out all the SERVER variables.  You might find one usefull:

$out = print_r($_SESSION, true);

$out = str_replace("\n", "<br>", $out);

$out = str_replace(' ', " ", $out);

print $out;

Answer 2

Show us some of your code, that way we may better help you.

You have a "URL" which brings you to another "URL". Indeed, do you even know what a URL is?

Why don't you just echo the variable containing the URL? I.E.

-----StartCode-----

<?php

echo '<p>' . $_SERVER['HTTP_HOST'] . '</p>';

?>

-----CodeEnd-----

If the URL is submitted through a form, it is likely that you can access it through the $_post or $_get variables. I.E.

-----StartCode-----

<?php

echo '<p>' . $_post['NAME'] . '</p>';

?>

-----CodeEnd-----

The "NAME" would refer to the name attribute of the form input element.

See also: http://php.net/reserved.variables - Predefined variables