PHYSICS HELP PLEASE! optics?

Question

A concave mirror has a focal length of 0.120 m. This mirror forms an image located 0.360 m in front of the mirror.

(a) where is this object located?

(b) What is this magnification?

(c) Is this image real or is it virtual?

(d) Is this image upright or is it inverted?

(e) Is this image enlarged or is it reduced in size?

Answer 1

A concave mirror has a focal length of 0.120 m. This mirror forms an image located 0.360 m in front of the mirror.

(a) where is this object located?

1/i +1/o = 1/f

1/o = 1/f - 1/i = (i-f)/(if)

o = if/(i-f) = 0.360 m*0.120 m. /( 0.360 m - 0.120 m)  = 0.180m

(b) What is this magnification?

m = -hi/ho = i/o = 0.360/0.120 = 3

(c) Is this image real or is it virtual?

real o > o

(d) Is this image upright or is it inverted?

inverted

(e) Is this image enlarged or is it reduced in size?

enlarged