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PLEASE HELP!!! The Kb of pyridine, C5H5N, is 1.5 x 10-9. Calculate the pH of a solution of 0.157 M pyridine.?

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The Kb of pyridine, C5H5N, is 1.5 x 10-9. Calculate the pH of a solution of 0.157 M pyridine.

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  1. C5H5N  in water --> C5H5NH+  &  OH-

    Kb = [C5H5NH+]  [OH-] / [C5H5N]

    1.5e-9 =  [x]  [x] / [0.157]

    X2 = 2.355e-10

    x = = [OH-] = 1.53e-5 molar

    pOH = 4.81

    14 - pOH = pH

    your answer = 9.19

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