PLEASE Help ME pre algebra!!!!?

Question

help me with this problem please!

A BRUSH COST $2 MORE THAN A COMB. THE BRUSH AND A COMB TOGETHER COST $3.78. FIND THE COST OF EACH.

please help me!!!

Answer 1

3.78 is the total price...say the comb is x and the brush is x+2....that means 2x+2=3.78...

so 3.78 minus 2 is 1.78 and so the equation becomes 2x=1.78

Divide 1.78 by 2 which is .89

Therefore the comb (x) is 89 cents

The brush(x+2) is $2.89

Answer 2

is sales tax included???

Answer 3

brush = $2.89

comb = $.89

Answer 4

if you need the work:

1. create equations

x - brush

y - comb

y+2=x     comb plus two bucks is the cost of brush

x + y = 3.78    comb plus brush = 3.78

2. make second equation equal x

x + y = 3.78  

goes to:

x = 3.78 - y

3. put equations together because they each equal x:

3.78 - y = y+2

4. solve for y

5. input y value into x+y=3.78, then solve for x

Answer 5

Let b be the cost of the brush and c be the cost of the comb. You can make two equations:

b = c + 2

b + c = 3.78

Because you know b = c + 2, then substitute c + 2 for b in the second equation:

b + c = 3.78

c + 2 + c = 3.78

2c + 2 = 3.78

2c = 1.78

c = 0.89

b = c + 2

b = 0.89 + 2

b = 2.89

ANSWER: The cost of the brush is $2.89 and the cost of the comb is $0.89.

Answer 6

Listen to the first girl!