PLease HELP! Simple Physics!?

Question

A car that is leaking oil at a constant rate is uniformly accelerated from rest starting out just when a drop falls. The first drop down the road is 0.80m from the car's starting point. How far from the starting point is the 4th drop?

Answer 1

♠ rate of dripping drops is good for measuring time (sort of stop watch);

path of the car is p=0.5a*t^2;

if t=1 and p=0.8m then acceleration is a=2p/t^2 =2*0.8/1^2 =1.6 m/drop^2;

if t=4 then p=0.5*a*t^2 = 0.5*1.6*4^2 =12.8m;