Question:

Paint Town sold 45 paintbrushes, 1 kind at 48.50 each and another at $9.75 each. ?

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In all, $398.75 was taken in for the brushes. How many of each kind were sold?

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  1. i know you use algebra for that, but. i forgot.


  2. ATTENTION: the correct sentence for the problem is:

    Paint Town sold 45 paintbrushes, 1 kind at $8.50 each and another at $9.75 each.

    So the price for the first type of paintbrushes is $8.50, not 48.50. That is asker's misspelling.

    let's say they sold x paintbrushes at $8.50 each and y paintbrushes at $9.75 each

    then you have:

    x * 8,5 + y * 9.75 = 398.75

    and

    x + y = 45     | *(-8.5)

    Multiply the second equation with -8.5. Then you have:

    8,5x + 9.75y = 398.75

    and

    -8.5x - 8.5y = -382.5    ( -45 * 8.5 = -382.5)

    Now add the 2 equations in only one, term by term (left terms and right terms):

    8,5x + 9.75y - 8.5x - 8.5y = 398.75 - 382.5 =>

    9.75y - 8.5y = 16.25 =>

    1.25y = 16.25 =>

    y = 16.25/1.25 =>

    y = 13

    Now, let's find the value of x. Consider the second equation from the system at the begining of this reply:

    x + y = 45

    replace y with 13:

    x + 13 = 45 => x = 45 - 13 => x = 32

    So the solution is:

    x = 32 and y = 13, which means:

    They sold

    32 paintbrushes at $8.50 each

    and

    13 paintbrushes at $9.75 each

  3. Hmmm..I think there's something wrong with the question but I don't know exactly what is it. If the paint town sold  45 paintbrushes at $9.75, that only kind of brush will cost $438.75. How about the paintbrush costing $48.50? And besides in $398.75 there will only be 8 $48.50 paintbrushes.

  4. set up your equations first.  You need a system of 2 equations with 2 variables.

    You have 2 types of brushes, x and y.  You sold 45 total, so x+y=45

    You know x sold for 48.50 and y sold for 9.75 each and you made 398.75

    So, 48.50x + 9.75y = 398.75

    See if you can get it from there....

  5. Let

    X = number of Type 1 paintbrushes sold

    Y = number of Type 2 paintbrushes sold

    Equation 1 -- Paint Town sold 45 paintbrushes

    X + Y = 45

    Equation 2 -- 1 kind at 48.50 each and another at $9.75 each.



    48.50X + 9.75Y = 398.75

    << How many of each kind were sold? >>

    From Equation 1, Y = 45 - X and substituting this in Equation 2,

    48.50X + 9.75(45 - X) = 398.75

    48.50X + 438.75 - 9.75X = 398.75

    38.75X = 398.75 - 438.75

    38.75X = -40  --- from this, it is obvious that there is something wrong with the data given in the problem. The right hand side of the equation cannot be a negative number.

  6. x+y=45

    Because of the $ and 4 are together I assume that it is $ 8.50 and $9.75 is for the other and also that for common sense that one brush would be so much than another and there is no solution if it is a 4

    x+y=45

    8.5x+9.75y=398.75

    x=45-y

    8.5(45-y)+9.75y=398.75

    382.50-8.5y+9.75y=398.75

    1.25y= 16.25

    y=13

    x=32

    32*8.5=272.00

    13*9.75=126.75

    --------------------------

    45 brushes @ 398.75

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