Parallel and Perpendicular Lines (Algebra 2)?

Question

We just started this topic of parallel and perpendicular lines and i am having trouble understanding it. here is two problems i dont get. could someone please explain to me how you do these?

1) Write an equation in slope-intercept form of a line paralled to line : and passing through point P: L: x+2y=3; P(2,0)

2) Write and equation in standard form of a line perpendicular to line L passing through point P: L: x-3y=-2; P(-1,2)

Answer 1

Parallel lines have the same slope, but different y intercepts.  So, to do number one you would solve for y and get the slope of that line, put into y = mx + b format and plug in (2,0) for x and y in the equation to get the y-intercept (b).

Perpendicular lines have slopes that are negative reciprocals of each other.  So if the slope was 5, the slope of the line perpendicular to it would be -1/5.  So solve for y, do that, and again just plug in your point to get the y-intercept, and you have it.

Answer 2

if it is parallel it has to have the same slope. if it is perpendicular it has to have the opposite slope. then it have to have the y-intercept from point P.