Parallel circuits? Resistance and current

Question

There are three bulbs arranged in parallel with a certain resistance. There is also an ammeter place at the starting of the circuit before the current splits.

Then, the resistance of the three identical bulbs are doubled. What will happen the the reading in the ammeter. Explain why. =D

Thanks for helping! =D

Answer 1

double the resistance, the current is cut in half.

why? ohms law.

.

Answer 2

Original :

1/Rt = 1/R + 1/R + 1/R

1/Rt = 3/R

Rt = R/3

It = V/Rt = 3V/R

After doubling each resistance:

1/Rt = 1/2R + 1/2R + 1/2R

1/Rt = 3/2R

Rt = 2R/3

It = V/Rt = 3V/2R = (1/2) * (3V/R)

therefore the total current is halved.

Answer 3

if you double the resistance your amps will increase trying to bypass the extra resistance. .........tom

Answer 4

The ammeter measures the Electric current,  and it would not 'change' unless it was on the other side of the resistors.

But the electric current will stay the same until it is slowed down by anything.

Hope this helped XD