Percentage error question?

Question

When we measured a volume of a beaker it came out 1016.2 mL, but the theoretical value was 1018.015 mL.......

How do i figure out the percentage error for my experiment?

Answer 1

Your error was 2.185 mL.  This is 2.185/1018.015=0.002146 of the accepted value, which is 0.215%.

Answer 2

you were off by 0.18%

1-(1016.2 / 1018.015) = .0018  or 0.18%

Check your work 1016.2 * 1.0018=  1018.015

1016.2 * .0018 = 1.82

1016.2 + 1.82 = 1018.02

Answer 3

i think you mixed up your terms, the theoretical value is what you experimented with and the accepted calue is what it' supposed to be

((accepted - theoretical)/accepted) x100

((1018.015 - 1016.2) / 1018.015) x 100

Answer 4

%Error = [ (|experimental value - theoretical value| )   /  theoretical value] x 100

So

%Error = [|1016.2mL - 1018.015mL| / 1018.015mL] x 100

%Error = 0.178%