Phys. Terminal Velocity???

Question

An object falling under the pull of gravity is acted upon by a frictional force of air resistance. The magnitude of this force is approximately proportional to the speed of the object, which can be written as f = bv. Assume that b = 12 kg/s and m = 59 kg.

Answer 1

Drag force is proportional to speed only in the laminar-flow region, which does not apply for a commonplace object such as a ball or a rock falling through air. For such cases, F is roughly proportional to v^2, as someone else has noted.

Answer 2

A falling object will be at the terminal velocity when the gravitational force (Fg = m*g) is equal to the drag force (Fd = b*v).  So the terminal velocity, v = m*g/b

Answer 3

Interesting,. I have always heard that the force due to air friction varies with the square of the speed.