Physicks question related specific heat, help???????//

Question

When a 120 g sample of aluminum (Al) absorbs 9612 J of energy, its temperature increases from 25°C to 115°C. What is the specific heat of Aluminum?>>>>>> i don't understand what the units used for this answer i got 675,000???, is that right???

Answer 1

Q = cm∆T

Tf = 115 C = 388.15 K

Ti = 25 C = 298.15 K

∆T = 388.15 K - 298.15 K

∆T = 90

c = Q/m∆T

c = 9612 J /120 g * (90 K)

c = .89 J /gK

http://en.wikipedia.org/wiki/Specific_he...

Answer 2

the answer for sure is .89j

Answer 3

Heat absorbed Q = m s (Tf- Ti)

9612 (J) = 0.120 (kg) * s * (115 - 25) (deg C)

s = specific heat = 9612 (J)/[0.120 * 90]kg-C

s = 890 Joule/kg-deg C