Physics - Ch 3 #141 h/w

Question

A 0.800 kg block is attached to a spring with spring constant 15 N/m. While the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 33 cm/s.

What is the amplitude of the subsequent oscillations?

What is the block's speed at the point where x= 0.40 A?

Answer 1

Given:

m = 0.8 kg

k = 15 N/m

v(i) = 33 m/s

First, find the angular frequency:

ω = sqrt(k/m) = ...

Use that to find the amplitude:

A = v(i) / ω = ...

Use both of those to find the velocity @ x = 0.4A (using v = A * ω):

v(x) = 0.4A * ω = ...