Physics Equation; Im Stuck!?

Question

Calculate the instantaneous speed (in m/s) at the 10 second mark for a car that accelerates at 2m/s^2 from a position of rest.

x = vo + at = 0 + (2m/s^2)(10s) = ?

How do I multiply this?

Answer 1

Of, for crying out loud.  What is 2 times 10?

Edit:  Honey, I apologize if I was harsh in that answer, but you copied and pasted my first answer to you, which did everything but multiply the final answer out, and then you ask someone to do it for you.  You're in physics.  That makes you either a junior or a senior.  You must have taken and passed algebra I with sufficiently high grades, and you must have taken and passed algebra II or at least be taking it now.  You should be capable of doing this on your own.  If not, you seriously need to rethink taking physics.

Answer 2

v = vo + at, where v is final/instantaneous velocity, vo is initial velocity, a is acceleration, and t is time.

t = 10s

a = 2m/s^2

vo = 0 m/s

Substitute values to eqtn:

v = 0 + (2m/s^2)(10s)

(m/s^2)(s) = m/s

So, v = 2(10)(m/s)

Thus, the instantaneous speed for the car is 20m/s at the 10-second mark.

Answer 3

what you have wrote is Not even a formula sorry to be harsh... here is what you need to do first find the distance it travels in 10 sec.  we know that starting point is at 0 b/c it says its initial position is at rest.  

now to find the final distance(xfinal)

x=v(initial)t+ .5at^2

x=0+.5(2m/s^2)(10s^2)

x=100m

we know x(initial),v(initial),t(initial)=0

Delta means final - initial

now to find instantaneous speed = delta x / delta time

100-0m/10-0s = 10m/s