Physics Help!!! 10 pts best answer!?

Question

when a cannon is aimed at an angle of 45 degrees above the horizontal, a cannon ball lands 100 meters down range. What was the muzzle velocity of the cannon ball?

Please show any formulas used and answer

Answer 1

The range of a projectile launched at velocity v0 and at angle θ is

R = 2*(v0²/g)sinθcosθ = (v0²/g)*sin2θ

For θ = 45º, 2θ = 90º and sin90º = 1, so the range for a 45º angle is

R = v0²/g

For R = 100m, v0 = √[100*g]